Question

Identify the vertex and the axis of symmetry of the parabola. Identify pointscorresponding to P and Q.(1, 1), x = 1P'(2, 2), Q'(-1.5)(1, 1). x = 1P'(0, 2), Q'(2.0)(1, 1), x = 1P(2.2), Q1-1,5)(1, 1), x = 1PO, 2). Q'12,0)

Answer 1

The vertex is the minimum/maximum point of the parabola.

This parabola has a dip, minimum point.

Looking at the coordinates, the vertex is at:

Vertex = (1,1)

The axis of symmetry is always the x-coordinate of the vertex coordinate.

That is x = 1.

So,

Axis of Symmetry:

x = 1

Now,

Since x = 1 (vertical line) is the axis of symmetry, we reflect the points P and Q about this line and find the points P' and Q'.

P' = (2,2)

Q' = (-1,5)