Respuesta :

[tex]\begin{gathered} m\angle D+m\angle E+m\angle F=180 \\ m\angle D=3x+5 \\ m\angle E=4x-15 \\ m\angle F=2x+10 \\ 3x+5+4x-15+2x+10=180 \\ 9x=180 \\ x=\frac{180}{9} \\ x=20 \end{gathered}[/tex][tex]\begin{gathered} m\angle D=65 \\ m\angle E=65 \\ m\angle F=50 \end{gathered}[/tex]

Therefore:

[tex]DF=FE[/tex]

RELAXING NOICE
Relax