Question

What is the solution set for -4 x - 10 ≤ 2?

Answer 1

$-4x-10\le2$

Adding 10 to both sides.

$\begin{gathered} -4x-10+10\le2+10 \\ -4x\le12 \\ \text{ Dividing both sides by -4, we have} \\ \frac{-4x}{-4}\ge\frac{12}{-4} \\ x\ge-3 \end{gathered}$

So the solution set is the set

$\mleft\lbrace x\in\mathfrak{\Re }\colon x\ge-3\mright\rbrace$