Explanation:
One mol of a gas at STP (standard conditions of pressure and temperature) occupies 22.4 L. So we can convert the mass of sulfur dioxide to moles and then use that relationship to get the answer to our problem.
To convert from grams to moles we will use the molar mass of sulfur dioxide.
sulfur dioxide = SO₂
molar mass of S = 32.07 g/mol
molar mass of O = 16.00 g/mol
molar mass of SO₂ = 1 * 32.07 g/mol + 2 * 16.00 g/mol
molar mass of SO₂ = 64.07 g/mol
moles of SO₂ = 325 g * 1 mol/(64.07 g)
moles of SO₂ = 5.07 moles
We said that 1 mol of SO₂ at STP will occupy 22.4 L, let's find the volume at STP of 5.07 moles.
Answer:
