QUestion 3.
Given:
Number of identical bricks intially weighed = 6
Additional brick weighed = 3 pounds
Total = 27 pounds of chocolate
Let's draw a tape diagram for this situation.
We have:
6x + 3 = 27
Let's solve for x.
Subtract 3 from both sides:
6x + 3 - 3 = 27 - 3
6x = 24
Divide both sides by 6:
[tex]\begin{gathered} \frac{6x}{6}=\frac{24}{6} \\ \\ x=4 \end{gathered}[/tex]
We have the tape diagram below:
