Question

you don't have to show me how to do it you can just put the answer

Answer 1

The form of the linear equation is

$y=mx+b$

m is the slope of the line

b is the y-intercept

Since the slope of the line is -4, then

m = -4

$y=-4x+b$

To find b substitute x and y in the equation by the coordinates of a point on the line

Since point (1, 2) lies on the line, then

x = 1

y = 2

$\begin{gathered} 2=-4(1)+b \\ 2=-4+b \end{gathered}$

Add 4 to both sides

$\begin{gathered} 2+4=-4+4+b \\ 6=b \end{gathered}$

Then the equation of the line is

$y=-4x+6$

To put it in the slope point form use this form

$y-y_1=m(x-x_1)$

m = -4

x1 = 1

y1 = 2

$y-2=-4(x-1)$

The answer is

$y-2=-4(x-1)$