Wehave the following:
[tex]\begin{gathered} 2x+4y=24 \\ -12x+y=-16 \end{gathered}[/tex]solving:
[tex]\begin{gathered} 2x+4y=24\Rightarrow\frac{2}{2}x+\frac{4}{2}y=\frac{24}{2}\Rightarrow x+2y=12\Rightarrow x=12-2y \\ \text{replacing} \\ -12\cdot(12-2y)+y=-16 \\ -144+24y+y=-16 \\ 25y=-16+144 \\ y=\frac{128}{25} \end{gathered}[/tex]now, para x
[tex]\begin{gathered} x=12-2\cdot\frac{128}{25} \\ x=\frac{44}{25} \end{gathered}[/tex]The answer is x = 44/25 and y 128/25