Question

Can you please help me out with a question

Answer 1

The volume of the pyramid and the cone is given by:

$V=\frac{1}{3}Bh$

where B is the area of the base and h is the height.

In this case the volume of pyramid is:

$V=\frac{1}{3}(10)(15)(12)=600$

The volume of the cone is:

$V^{\prime}=\frac{1}{3}\pi(4.5)^2(12)=81\pi$

Therefore the remaining volume is:

$V=600-81\pi=345.5$

Therefore the volume is 345.5 cubic units.