The line passes through the points (-2,-3) and (-1,0).
The general equation of line passes through the point (x_1,y_1) and (x_2,y_2) is,
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]Determine the equation of line.
[tex]\begin{gathered} y-(-3)=\frac{0-(-3)}{-1-(-2)}(x-(-2)) \\ y+3=\frac{3}{1}(x+2) \\ y=3x+6-3 \\ y=3x+3 \end{gathered}[/tex]Linear equation of line is y = 3x +3.