Being CE parallel to BA, and CD in the same line, CD is parallel to BA.
We also know BC is parallel to DA. All this means ABCD is a parallelogram
Under these conditions, angle BAD is congruent to angle C. Thus, angle BAD has a measure of 63°.
In a parallelogram, every pair of consecutive angles add up to 180°, thus CDA has a measure of 180° - 63° = 117°.
Angle EDA is congruent to angle C, thus its measure is 63°
Since DE is congruent to AE, triangle EDA is isosceles and the measure DAE is 63°. Finally the required angle is BAE= 63° + 63° = 126°
