Find the density of a plastic triangular pyramid with a height of 5 feet. The base of the pyramid has a height of 4 feet and a base length of 3 feet. The mass is 56 kilograms.

Respuesta :

The base length of triangular pyramid is b = 3 feet.

The height of the base of triagular pyramid is h = 3.

The height of triangular pyramid is H = 5 feet.

The mass of the triangular pyramid = 56 kg.

The formula for the volume of the pyramid is,

[tex]\begin{gathered} V=\frac{1}{3}\cdot B\cdot H \\ =\frac{1}{3}\cdot(\frac{1}{2}bh)\cdot H \\ =\frac{1}{6}b\cdot h\cdot H \end{gathered}[/tex]

Substitute the values in the formula to determine the volume of pyramid.

[tex]\begin{gathered} V=\frac{1}{6}\cdot3\cdot4\cdot5 \\ =10 \end{gathered}[/tex]

The formula for the density of the platic is,

[tex]\rho=\frac{M}{V}[/tex]

Substitute the vlaues in the formula

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