Notice the pattern below
[tex]\begin{gathered} 9.75+15\%*9.75=9.75(1+0.15)\rightarrow first\text{ year} \\ (9.75(1+0.15))+0.15(9.75(1+0.15))=9.75(1+0.15)(1+0.15)=9.75(1+0.15)^2\rightarrow second\text{ year} \\ ... \\ \Rightarrow9.75(1+0.15)^n\rightarrow\text{ nth year} \end{gathered}[/tex]Therefore, setting n=12,
[tex]\Rightarrow C=9.75(1+0.15)^{12}=9.75(1.15)^{12}=52.1649...[/tex]