Answer:
• Discriminant =0
,• Number of Solutions = One repeated root
Explanation:
Given the quadratic equation below:
[tex]2x^2+12x+20=2[/tex]First, we express it in the general form of a quadratic equation: ax²+bx+c=0
[tex]\begin{gathered} 2x^2+12x+20-2=0 \\ 2x^2+12x+18=0 \\ \implies a=2,b=12,c=18 \end{gathered}[/tex]Next, we find the discriminant.
[tex]\begin{gathered} \text{Discriminant,}D=b^2-4ac \\ =12^2-4(2)(18) \\ =144-144 \\ D=0 \end{gathered}[/tex]Since the discriminant equals 0.
The quadratic equation has One Repeated Root.