For this question, we will use the formula for the area of a trapezium:
[tex]\begin{gathered} A=\frac{(B+b)h}{2}\text{.} \\ \text{Where B is the larger base, b is the smaller base and h is the height of the trapezium.} \end{gathered}[/tex]Substituting B=x, b=x-y we get:
[tex]A=\frac{(x+x-y)h}{2}=\frac{(2x-y)h}{2}=\frac{2xh-yh}{2}=xh-\frac{yh}{2}\text{.}[/tex]Answer:
[tex]xh-\frac{yh}{2}\text{.}[/tex]