Question

nth term of a sequence is 1/2 n^2+10 term closest to 100 clear explanation pleasse

Answer 1

Given:

$t_n=\frac{1}{2}n^2+10$$\begin{gathered} 100=\frac{1}{2}n^2+10 \\ 90=\frac{1}{2}n^2 \\ 180=n^2 \\ n=\sqrt[]{180} \\ n=13.4164 \end{gathered}$

13 th term is closest to 100.