Answer:
0.10625 and -2.35625
Explanation:
Given the equation;
4x^2+9x = 1
4x^2 + 9x - 1 = 0
From the equation a = 4, b = 9 and c = -1
Substitute into the formula;
[tex]\begin{gathered} x\text{ = }\frac{-b\pm\sqrt[\square]{b^2-4ac}}{2a} \\ x\text{ = }\frac{-9\pm\sqrt[\square]{81-4(4)(-1)}}{2(4)} \\ x\text{ =}\frac{-9\pm\sqrt[\square]{81+16}}{8} \\ x\text{ }\frac{-9\pm\sqrt[\square]{97}}{8} \\ x\text{ = }\frac{-9\pm9.85}{8} \\ x\text{ = }\frac{-9+9.85}{8}\text{ and }\frac{-9-9.85}{8} \\ x\text{ = 0.85/8 and -18.85/8} \\ x\text{ = }0.10625\text{ and -}2.35625 \end{gathered}[/tex]Hence the value of x are 0.10625 and -2.35625
