find the slope of the line that passes though the given points

1. (7,3) and (13,8)
[tex]\text{slope}=\frac{y2-y1}{x2-x1}=\frac{8-3}{13-7}=\frac{5}{6}[/tex]2. ( -5,2) and ( -1, -6)
[tex]\text{slope}=\frac{-6-2}{-1-(-5)}=\frac{-8}{-1+5}=\frac{-8}{4}=-2[/tex]3. (9, -3) and (9,4)
[tex]\text{slope}=\frac{4-(-3)}{9-9}=\frac{4+3}{0}=\frac{7}{0}\text{ }[/tex]4. ( -2, -4) and ( -11, -7)
[tex]\text{slope}=\frac{-7-(-4)}{-11-(-2)}=\frac{-7+4}{-11+2}=\frac{-3}{-9}=\frac{1}{3}[/tex]