Given:
[tex]4^4\div(3^2+(3^2-5^0))[/tex]To: Solve the given expression
Apply the laws basic of operation PODMAS
The operation consist of:
Parentheses
Division
Let us solve the parentheses first, then division
[tex]\begin{gathered} 4^4\div(3^2+(3^2-5^0)) \\ (3^2+(3^2-5^0))=(3^2+(9-1)) \\ (3^2+(9-1))=(9+8)=17 \\ \text{Therefore, we have:} \\ 4^4\div(3^2+(3^2-5^0))=256\div17=15\frac{1}{17} \end{gathered}[/tex]Hence, the final answer is 15 1/17