Respuesta :

The base of the pyramid is a square, and its area is calculated as follows:

[tex]\begin{gathered} B=side^2 \\ B=4^2 \\ B=16\text{ yd}^2 \end{gathered}[/tex]

Given that the base is a square, its perimeter is calculated as follows:

[tex]\begin{gathered} P=4\cdot\text{side} \\ P=4\cdot4 \\ P=16\text{ yd} \end{gathered}[/tex]

The slant height, l, is shown in the diagram, its measure is l = 6 yd.

Finally, the surface area, SA, is:

[tex]\begin{gathered} SA=B+\frac{1}{2}Pl \\ SA=16+\frac{1}{2}\cdot16\cdot6 \\ SA=16+48 \\ SA=64\text{ yd}^2 \end{gathered}[/tex]

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