Given that: mACD= (12.x+ 15) mBCE=(20x- 9) Find mLDCE in degrees.

ACD and BCE are vertical angles, so its measures are the same.
DCE is supplementary to ACD, so both angles add 180 degrees.
From the first sentence, we can write:
[tex]\begin{gathered} \text{mACD}=\text{mBCE} \\ 12x+15=20x-9 \\ 15+9=20x-12x \\ 24=8x \\ x=\frac{24}{8} \\ x=3 \end{gathered}[/tex]Then we can write the equation for DCE as:
[tex]\begin{gathered} \text{mDCE}+\text{mACD}=180 \\ \text{mDCE}=180-\text{mACD} \\ \text{mDCE}=180-(12x+15) \\ \text{mDCE}=180-12\cdot3-15 \\ \text{mDCE}=180-36-15 \\ \text{mDCE}=129 \end{gathered}[/tex]The measure of DCE is 129 degrees.