Please help me with this i need to solve for m<2

Given:
m∠WXZ = 103°.
And
m∠WXZ =m∠1 + m∠2
Then:
m∠1 + m∠2 = 103°
Moreover:
m∠1 = 1 +m∠2
Let's substitute m∠1 by 1 +m∠2 and find m∠2:
[tex]\begin{gathered} m∠1+m∠2=103° \\ 1+m∠2+m∠2=103° \\ 1+2m∠2=103° \end{gathered}[/tex]Subtracting 1 from both sides and then dividing both sides by 2:
[tex]\begin{gathered} 1+2m∠2-1=103-1 \\ 2m∠2=102 \\ \frac{2m∠2}{2}=\frac{102}{2} \\ m∠2=51° \end{gathered}[/tex]Now, let's find m∠1:
[tex]\begin{gathered} m∠1=1+m∠2 \\ m∠1=1+51 \\ m∠1=52° \end{gathered}[/tex]Answer: m∠2 = 51°.