Question

if 6x²y² were factored out from 24x²y³ - 18x³y² the binomial left would be?

Answer 1

We have to find the binomial that is left when 6x²y² is factored out from 24x²y³-18x³y².

To do that we have to dividice the original expression by the factor. We can do this as:

$\begin{gathered} \frac{24x^2y^3-18x^3y^2}{6x^2y^2} \\ \frac{24x^2y^3}{6x^2y^2}-\frac{18x^3y^2}{6x^2y^2} \\ \frac{24}{6}\cdot\frac{x^2}{x^2}\cdot\frac{y^3}{y^2}-\frac{18}{6}\cdot\frac{x^3}{x^2}\cdot\frac{y^2}{y^2} \\ 4\cdot1\cdot y-3\cdot x\cdot1 \\ 4y-3x \end{gathered}$

Answer: the binomial left would be 4y-3x.