Respuesta :

ANSWER :

The zeros are -1, 3i and -3i

EXPLANATION :

From the problem, we have :

[tex]f(x)=x^3+x^2+9x+9[/tex]

Factor completely :

[tex]\begin{gathered} f(x)=x^2(x+1)+9(x+1) \\ f(x)=(x^2+9)(x+1) \end{gathered}[/tex]

Zeros are values of x when f(x) = 0

That will be :

[tex]0=(x^2+9)(x+1)[/tex]

Equate both factors to 0.

[tex]\begin{gathered} x^2+9=0 \\ x^2=-9 \\ x=\sqrt{-9} \\ x=3i\quad and\quad x=-3i \end{gathered}[/tex][tex]\begin{gathered} x+1=0 \\ x=-1 \end{gathered}[/tex]

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