Solution:
Composite numbers are numbers with more than two factors. They are divisible by more than two numbers.
Given the numbers:
[tex]29,\text{ 37, 57, 41, 31}[/tex][tex]\begin{gathered} \Rightarrow29\text{ is not a composite number since it has only 2 factors \lparen1 and 29\rparen.} \\ \Rightarrow37\text{ is not a composite number since it has only 2 factors \lparen1 and 37\rparen.} \\ \Rightarrow57\text{ is divisible by 1, 3, 19, and 57. Thus, it's a composite number.} \\ \Rightarrow41\text{ is not a composite number since it has only 2 factors \lparen1 and 41\rparen.} \\ \Rightarrow31\text{ is not a composite number since it has only 2 factors \lparen1 and 31\rparen.} \end{gathered}[/tex]Hence, 57 is a composite number.
The correct option is C.