Since the right triangle is isosceles, the legs have the same length.
So the other leg is also √5 cm.
Now, to calculate the hypotenuse, we can use Pythagorean theorem:
[tex]\begin{gathered} h^2=(\sqrt[]{5})^2+(\sqrt[]{5})^2 \\ h^2=5+5 \\ h^2=10 \\ h=\sqrt[]{10} \end{gathered}[/tex]