Respuesta :

Given:

The triangle is a right angle triangle then:

Use pythagorean theorem is:

[tex]\text{hypotenuse}^2=base^2+perpendicular^2[/tex]

Here,

[tex]\begin{gathered} \text{hypotenuse}=61 \\ \text{base}=60 \\ \text{perpendicular}=H \end{gathered}[/tex]

[tex]\begin{gathered} (61)^2=(60)^2+(H)^2 \\ 3721=3600+H^2 \\ H^2=3721-3600 \\ H^2=121 \\ H=\sqrt[]{121} \\ H=\sqrt[]{(11)^2} \\ H=11 \end{gathered}[/tex]

So value of "H" is 11.

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