Given the expression:
[tex]-7\frac{2}{3}+(-5\frac{1}{2})+8\frac{3}{4}[/tex]First, we open the bracket:
[tex]=-7\frac{2}{3}-5\frac{1}{2}+8\frac{3}{4}[/tex]Next, change each of the fraction to an improper fraction
[tex]=-\frac{23}{3}-\frac{11}{2}+\frac{35}{4}[/tex]We look for the lowest common multiple of the denominators.
LCM of 3, 2 and 4=12
Therefore:
[tex]\begin{gathered} -\frac{23}{3}-\frac{11}{2}+\frac{35}{4}=\frac{-23(4)-11(6)+35(3)}{12} \\ =\frac{-92-66+105}{12} \\ =-\frac{53}{12} \\ =-4\frac{5}{12} \end{gathered}[/tex]
