Question

Determine the values of x, y and Z

Answer 1

Consider the figure,

From the right angled triangle ABD, using Pythagoras theorem, we have,

$\begin{gathered} Hypote\nu se=\sqrt[]{base^2+height^2} \\ y=\sqrt[]{16^2+6^2} \\ \text{ =}17.08=17.1 \end{gathered}$

FRom the angle bisector theorem, we have,

$\frac{AB}{BC}=\frac{AD}{CD}$

That is, we have,

$\begin{gathered} \frac{16}{x}=\frac{17.1}{z} \\ \end{gathered}$

Thus, second option is correct.