How can i solve this ? what the steps too solving this !

Given:
[tex]\begin{gathered} \angle DEH=13x \\ \angle FEH=10x+21 \end{gathered}[/tex]To find the value of x:
Since, the angles DEH and FEH are the complementary angles.
So,
[tex]\begin{gathered} \angle DEH+\angle FEH=90^{\circ} \\ 13x+10x+21=90^{\circ} \\ 23x+21=90^{\circ} \\ 23x=90^{\circ}-21^{\circ} \\ 23x=69 \\ x=\frac{69}{23} \\ x=3 \end{gathered}[/tex]Hence, the value of x is 3.
Thus, the angles
[tex]\begin{gathered} \angle DEH=13x \\ =13(3) \\ =39^{\circ} \end{gathered}[/tex]And
[tex]\begin{gathered} \angle FEH=10x+21 \\ =10(3)+21 \\ =30+21 \\ =51^{\circ} \end{gathered}[/tex]Hence,
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