When x = , what is the value of ? 3 F. 2. G. 2 anai 5 H. 2 J. 5 K 10

The question given to us says we should evaluate the expression below:
[tex]\frac{8x-3}{x}[/tex]when
[tex]x=\frac{1}{2}[/tex]To evaluate the expression, we simply substitute the value of x i.e. 1/2, into the expression and then simplify.
This is done below
[tex]\begin{gathered} \frac{8x-3}{x} \\ \text{put x=}\frac{1}{2} \\ \\ \frac{8(\frac{1}{2})-3}{\frac{1}{2}} \\ \end{gathered}[/tex]Now, let us simplify the above expression. Also remember that when we are dividing by a fraction, it is the same as multiplying by the denominator of that fraction.
In this case, we are dividing by 1/2, this is the same as multiplying by 2.
Hence,
[tex]\begin{gathered} \frac{8(\frac{1}{2})-3}{\frac{1}{2}} \\ \\ =\frac{4-3}{\frac{1}{2}}=1\times2 \\ \\ \therefore\text{The answer is: 2} \end{gathered}[/tex]Therefore, the final answer is 2