Respuesta :

The question given to us says we should evaluate the expression below:

[tex]\frac{8x-3}{x}[/tex]

when

[tex]x=\frac{1}{2}[/tex]

To evaluate the expression, we simply substitute the value of x i.e. 1/2, into the expression and then simplify.

This is done below

[tex]\begin{gathered} \frac{8x-3}{x} \\ \text{put x=}\frac{1}{2} \\ \\ \frac{8(\frac{1}{2})-3}{\frac{1}{2}} \\ \end{gathered}[/tex]

Now, let us simplify the above expression. Also remember that when we are dividing by a fraction, it is the same as multiplying by the denominator of that fraction.

In this case, we are dividing by 1/2, this is the same as multiplying by 2.

Hence,

[tex]\begin{gathered} \frac{8(\frac{1}{2})-3}{\frac{1}{2}} \\ \\ =\frac{4-3}{\frac{1}{2}}=1\times2 \\ \\ \therefore\text{The answer is: 2} \end{gathered}[/tex]

Therefore, the final answer is 2

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