Question

-2(6 - 3n) + 27n = -3(n - 8)

Answer 1

We want to solve the following

$\text{ -2(6-3n)+27n =-3(n-8)}$

First we distribute each multiplication on each side, so we get

$\text{ - 12 }+6n+27n=\text{ -3n+24}$

If we operate on the left side, we get

$\text{ -12 +33n= -3n+24}$

Now, we add 3n on both sides, so we get

$24\text{ = -12+33n+3n = -12+36n}$

Then, we add 12 on both sides, so we get

$36n=24+12=36$

Finally, we divide boths sides by 36, so we get

$n=\frac{36}{36}=1$

So the value of n is 1