Given
[tex]\begin{gathered} \bar{x}=3.1 \\ \sigma=0.85 \\ \alpha=0.05 \\ n=25 \end{gathered}[/tex]Compute the z statistic;
[tex]z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt[]{n}}}[/tex][tex]z=\frac{\frac{3.1-2.7}{0.85}}{\sqrt[]{5}}=0.094[/tex]Using a table to compute the p value, we have;
[tex]p=0.92511>0.05[/tex]Thus, we fail to reject the null hypothesis. There is not enough evidence to oppose the company's claim