Question

Function g defined by g(x)=3-x^2, x ER evaluate:g(-3) and g(1/2)

Answer 1

Given

$g(x)=3-x^2$

To find the values of g(-3) and g(1/2).

Explanation:

It is given that,

$g(x)=3-x^2$

Then, for x=-3,

$\begin{gathered} g(-3)=3-(-3)^2 \\ =3-9 \\ =-6 \end{gathered}$

Also, for x=1/2,

$\begin{gathered} g(\frac{1}{2})=3-(\frac{1}{2})^2 \\ =3-\frac{1}{4} \\ =\frac{12-1}{4} \\ =\frac{11}{4} \end{gathered}$

Hence, the answer is -6 and 11/4.