Question

6x+4y=16.703x+4y=10.85

Answer 1

We have this system of equations

$\begin{gathered} 6x+4y=16.70\ldots(1) \\ 3x+4y=10.85​\ldots(2) \end{gathered}$

First we will multiply the second equation by -1, so we obtain

$-3x-4y=-10.85$

then we sum the first equation with the equation above

$\begin{gathered} 3x=5.85 \\ \end{gathered}$

then we clear x

$x=\frac{5.85}{3}=1.95$

then we substitute the value of x in the first equation

$\begin{gathered} 6(1.95)+4y=16.70 \\ 11.7+4y=16.70 \end{gathered}$

then we clear y

$\begin{gathered} 4y=5 \\ y=\frac{5}{4} \\ y=1.25 \end{gathered}$

the solution of the system of equations is

x=1.95

y=1.25