Respuesta :

[tex]\text{Answer : y = }\frac{1}{4}x\text{ + 1}[/tex]

Let f(x) = y

When x = -4 , y = 0

when x = 4 , y = 2

[tex]\begin{gathered} x1\text{ = -4 -4, y1 = 0, x2 = 4, y2 = 2} \\ Firstly,\text{ find the slope} \\ \text{Slope = }\frac{rise}{\text{run}} \\ \text{Slope = }\frac{y2\text{ - y1}}{x2\text{ - x1}} \\ \text{Slope = }\frac{2\text{ - 0}}{4\text{ - (-4)}} \\ \text{Slope = }\frac{2}{4\text{ + 4}} \\ \text{Slope= }\frac{2}{8} \\ \text{Slope = }\frac{1}{4} \\ \text{The equation of a linear function} \\ y\text{ = mx + b} \\ (y\text{ - y1) = m(x -x1) } \\ (y\text{ - 0) = }\frac{1}{4}(x\text{ -(-4)} \\ y\text{ - 0 = }\frac{1}{4}(x\text{ + 4)} \\ y\text{ - 0 = }\frac{1}{4}x\text{ + }\frac{1\text{ x 4}}{4} \\ y\text{ - 0= }\frac{1}{4}x\text{ + 1} \\ y\text{ = }\frac{1}{4}x\text{ + 1} \\ \text{The linear function is y = }\frac{1}{4}x\text{ + 1} \end{gathered}[/tex]

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