Answer:
C. 1191.49 K.
Explanation:
Entropy and Free Energy => Temperature and Free Energy.
We can use the following formula that involves enthalpy (ΔH), entropy (ΔS), and temperature (T):
[tex]T=\frac{\Delta H}{\Delta S}.[/tex]You can see that the units of enthalpy are kJ/mol, and entropy is J/Kmol. You can realize that we cannot do the calculation with these units because the energy unit is not equal (kJ≠J), so we can convert the enthalpy, 280 kJ/mol to J/mol remembering that 1 kJ equals 1000 J like this:
[tex]280\frac{kJ}{mol}\cdot\frac{1000\text{ J}}{1\text{ kJ}}=280000\frac{J}{mol}.[/tex]So now we have ΔH = 280000 J/mol and ΔS = 235 J/Kmol and we can replace these data in the given formula:
[tex]\begin{gathered} T=\frac{280000\text{ }\frac{J}{mol}}{235\frac{J}{Kmol}}, \\ \\ T=1191.489\text{ K}\approx1191.49\text{ K.} \end{gathered}[/tex]The answer would be that the temperature is C. 1191.49 K.
