Question

A piece of unknown metal weighs 500 g. When the piece of metal absorbs 6.64 kJ of heat, its temperature increases from 25°C to 78°C. What's the specific heat capacityof this metal?A. 13 J/gºCB. 0.25 J/gºCC. 25 J/gºCD.2.5 J/g °C

Answer 1

Answer:

0.25 J/gºC

Explanations:

The formula for calculating the heat absorbed by the metal is expressed as:

$Q=mc\triangle t$

where;

m is the mass of the object

c is the specific heat capacity

△t is the change in temperature

Given the following parameters

m = 500g

△t = 78 - 25 = 53°C

Q = 6.64kJ = 6640Joules

Substitute

$\begin{gathered} 6640=500c(53) \\ c=\frac{6640}{500\times53} \\ c=\frac{6640}{26500} \\ c=\frac{0.25J}{g^oC} \end{gathered}$

Therefore the specific heat capacity of this metal is 0.25 J/gºC