Given:
The system of eqations is:
-3 x + 8y = 4
3 x - 2y =8
Reuired:
To find the solutions of x and y in the form of ordered pairs.
Explanation:
The system of equations is:
-3 x + 8y = 4 .......(1)
3 x - 2y =8 .........(2)
To eliminatet x add both equation (1) and (2).
[tex]\begin{gathered} \left(-3x+3x\right)+(8y-2y)=(4+8) \\ 6y=12 \\ y=\frac{12}{6} \\ y=2 \end{gathered}[/tex]
Now substitute the value of y in equation (1) and get the value of x.
[tex]\begin{gathered} -3x+8(2)=4 \\ -3x+16=4 \\ -3x=4-16 \\ -3x=-12 \\ 3x=12 \\ x=\frac{12}{3} \\ x=4 \end{gathered}[/tex]
Final Answer:
Thus the values of x and y in the form of ordered pair is (4,).
