Question

Solve the following quadratic equation by using the quadratic formula. If needed, submit your answer as a fraction reduced to lowest terms or round your answer to two decimal places

Answer 1

Solution

Solve the following quadratic equation by using the quadratic formula

$3z^2-2z=0$$z=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$\begin{gathered} 3z^2-2z+0=0 \\ a=3,b=-2,c=0 \end{gathered}$$\begin{gathered} z=\frac{-(-2)\pm\sqrt{(-2)^2-4(3)(0)}}{2(3)} \\ z=\frac{2\pm\sqrt{4}}{6} \\ z=\frac{2\pm2}{6} \\ z=\frac{2+2}{6},\frac{2-2}{6} \\ z=\frac{4}{6},\frac{0}{6} \\ x=\frac{2}{3},0 \end{gathered}$

Therefore the correct answer is

$z=\frac{2}{3},0$