You are buying dessert for your friend's birthday party. The Bake Shop sells cupcakes for $3 each and donuts for $2 each. Your budget is $42 for desserts.

You are buying dessert for your friends birthday party The Bake Shop sells cupcakes for 3 each and donuts for 2 each Your budget is 42 for desserts class=

Respuesta :

Here, we are told to identify the number of donuts with d and the number of cupcakes with c

a) Firstly, we want to write an equation relating the number of donuts and the number of cupcakes that can be bought

1 donut costs $2, so the cost of d donuts will be d * 2 = $2d

1 cupcake costs $3 , so the cost of cupcakes will be c * 3 = $3c

Now, using the budget, we can write an equation for the number of cupcakes and desserts that can be bought

Mathematically, that will be;

[tex]2d\text{ + 3c = 42}[/tex]

b) Now, given that c is 4, we want to calculate the value of d that will make the equation true

Mathematically, what we need to do here is to substitute c = 4 into the equation

We have;

[tex]\begin{gathered} 2d\text{ + 3(4) = 42} \\ 2d\text{ + 12 = 42} \\ \\ 2d\text{ = 42-12} \\ \\ 2d\text{ = 30} \\ \\ d\text{ = }\frac{30}{2} \\ \\ d\text{ = 15} \end{gathered}[/tex]

c) What the above means in the context of the equation we have written is that the number of donuts we can buy alongsides 4 cupcakes is 15

So, buying 4 cupcakes, we can afford to still buy 15 donuts from the budget

d) Here, we want to have a graph of the equation

From the plot, we are told to make the number of donuts the y-axis and the number of cupcakes on the y-axis

Generally, the equation of a linear model can be represented as;

[tex]\begin{gathered} y\text{ = mx + b} \\ \\ m\text{ is slope and b is y-intercept} \\ \end{gathered}[/tex]

Now, let us replace d with y and c with x; we have the result as;

[tex]\begin{gathered} d\text{ = cx + b} \\ \\ \text{Let us write the equation we have in this form} \\ \\ 2d\text{ + 3c = 42} \\ \\ 2d\text{ = -3c + 42} \\ \\ d\text{ = }\frac{-3c}{2}\text{ + 21} \end{gathered}[/tex]

So for our y-intercept ( the point at which the line touches the y-axis), we have the coordinate of the point as (21,0)

To get for ths x-intercept, replace d with 0;

[tex]\begin{gathered} \frac{3c}{2}\text{ = 21} \\ \\ 3c\text{ = 21 }\times\text{ 2} \\ \\ 3c\text{ = 42} \\ \\ c\text{ = }\frac{42}{3} \\ \\ c\text{ = 14} \end{gathered}[/tex]

S0, to graph the line, we simply join (21,0) on the y-axis with (14,0) on the x-axis

A plot representing this is given below;

Ver imagen HoldenT530911
ACCESS MORE
EDU ACCESS