Given the equation
[tex](x-4)^2-5[/tex]
We are asked to identify the vevrtex, complete the table and plot the graph of the function. This can be seen below.
Answer
The vertex form of a quadratic equation can be written as:
[tex]\begin{gathered} y=a(x-h)^2-k \\ \text{where (h,k) is the location of the vertex} \end{gathered}[/tex]
Therefore by comparison, the value of the vertex is
Answer A: (4,-5)
We can complete the table below by substituting the chosen value of x into the given function
We can then have the graph as:
