Given the rectangle ABCD, whose vertices are:
[tex]A\mleft(4,1\mright),B\mleft(2,3\mright),C\mleft(5,6\mright),D\mleft(7,4\mright)[/tex]
You can apply the transformations shown in each option, in order to determine all the transformations that will carry the figure onto itself:
• First option:
By definition, the rule for a rotation of 270 degrees counterclockwise is:
[tex](x,y)\rightarrow(y,-x)[/tex]
And the rule for a rotation of 90 degrees counterclockwise is:
[tex](x,y)\to(-y,x)[/tex]
Therefore, you can choose any vertex of the rectangle and apply the first rule and then the second rule:
[tex]A\mleft(4,1\mright)\rightarrow A^{\prime}\mleft(1,-4\mright)\rightarrow A^{\doubleprime}\rightarrow(4,1)[/tex]
Notice that the coordinates of point A'' are equal to the original point A.
• Second option:
The rule for a translation of 10 units left and 5 units down is:
[tex](x,y)\rightarrow(x-10,y-5)[/tex]
And the rule for a translation of 10 units right, and 5 units up is:
[tex](x,y)\rightarrow(x+10,y+5)[/tex]
Then, applying the transformations indicated, you get:
[tex]\begin{gathered} A\mleft(4,1\mright)\rightarrow A^{\prime}(4-10,1-5)=A^{\prime}(-6,-4) \\ \\ A^{\prime}(-6,-4)\rightarrow A^{\prime\prime}(-6+10,-4+5)=A^{\doubleprime}(4,1) \end{gathered}[/tex]
Notice that point A'' and point A are equal.
• Third option:
The rule for a reflection across the y-axis is:
[tex](x,y)\rightarrow\mleft(-x,y\mright)[/tex]
Then, applying that transformation and then applying the rule for a rotation of 270 degrees counterclockwise about the Origin (shown in the explanation of the First option), you get:
[tex]A(4,1)\rightarrow A^{\prime}(-4,1)\rightarrow A^{\doubleprime}(1,4)[/tex]
The points A and A'' are different.
• Fourth option:
The rule for a reflection across the x-axis is:
[tex](x,y)\rightarrow(x,-y)[/tex]
For a translation of 5 units left is:
[tex](x,y)\rightarrow(x-5,y)[/tex]
And for a translation of 5 units right:
[tex](x,y)\rightarrow(x+5,y)[/tex]
Therefore, knowing those rules and also knowing the rule for a reflection across the y-axis, you can apply all the transformations indicated in the third option, you get:
[tex]A\mleft(4,1\mright)\rightarrow A^{\prime}\mleft(4,-1\mright)\rightarrow A^{\doubleprime}(4-5,-1)=A^{\doubleprime}(-1,-1)[/tex]
[tex]A^{\doubleprime}(-1,-1)\rightarrow A^{\doubleprime}^{\prime}(1,-1)\rightarrow A^{\doubleprime\prime^{\prime}}(6,-1)[/tex]
Notice that the points A and A'''' do not have the same coordinates.
• Fifth option:
Knowing the rule for a reflection across the y-axis, and knowing that to translate a point 9 units right you must add 9 to the x-coordinate of the points, you get:
[tex]A\mleft(4,1\mright)\rightarrow A^{\prime}\mleft(-4,1\mright)\rightarrow A^{\doubleprime}(-4+9,1)=A^{\doubleprime}(5,1)[/tex]
Notice that the points A and A'' do not have the same coordinates.
Hence, the answers are:
• First option.
,
• Second option.