Geometry Angle of Depression and Angle of Elevation. 2. - 3.

2) We can draw this situation as:
We can now find the angle x.
We can use trigonometric ratios as:
[tex]\begin{gathered} \tan(x)=\frac{Opposite}{Adjacent}=\frac{23}{34} \\ x=\arctan(\frac{23}{34}) \\ x\approx34.08\degree \end{gathered}[/tex]3) We can draw this situation as:
We can find x as:
[tex]\begin{gathered} \tan(x)=\frac{Opposite}{Adjacent}=\frac{12}{17} \\ x=\arctan(12/17) \\ x\approx35.22\degree \end{gathered}[/tex]Answer:
2) 34.08°
3) 35.22°