Question

I have no idea what I'm doing so if you could please help me if like all three questions answered if at all possible

Answer 1

$V(h,k)=\text{vertex}$$\begin{gathered} h=\frac{-b}{2a} \\ k=f(h) \end{gathered}$$\begin{gathered} \text{For a given equation of the form:} \\ f(x)=ax^2+bx+c \end{gathered}$

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$\begin{gathered} f(x)=-2x^2 \\ a=-2 \\ b=0 \\ c=0 \\ h=\frac{-0}{2(-2)}=0 \\ k=f(0)=-2(0)^2=0 \end{gathered}$

Therefore:

vertex = V(0,0)

Since the axis of symmetry is located at the vertex: Axis of symmetry: x = 0