Question

AcellusUse the value of x to find themeasure of Angle 1.x = 25Z1 = [?]° 22 = [ 1°5x - 5/2x + 10Enter

Answer 1

x = 25

Therefore

$\begin{gathered} \angle1=5x-5 \\ \angle1=5(25)-5 \\ \angle1=125-5 \\ \angle1=120^{\circ} \end{gathered}$$\begin{gathered} \angle2=2x+10 \\ \angle2=2(25)+10 \\ \angle2=50+10 \\ \angle2=60^{\circ} \end{gathered}$