Respuesta :

Solution

We are given the function

[tex]f(x)=(\frac{1}{2})^x[/tex]

So we have the point

[tex]\begin{gathered} f(-2)=(\frac{1}{2})^{-2}=4 \\ \\ f(-1)=(\frac{1}{2})^{-1}=2 \\ \\ f(0)=(\frac{1}{2})^0=1 \\ \\ f(1)=(\frac{1}{2})^1=\frac{1}{2} \\ \\ f(2)=(\frac{1}{2})^2=\frac{1}{4} \end{gathered}[/tex]

The five points are

[tex]\begin{gathered} (-2,4) \\ (-1,2) \\ (0,1) \\ (1,\frac{1}{2}) \\ (2,\frac{1}{4}) \end{gathered}[/tex]

The asymptotes is

[tex]y=0[/tex]

The graph with the asymptotes is

Ver imagen AlizeeV546877
Ver imagen AlizeeV546877
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