Let's identify the sequence:
[tex]\begin{gathered} \frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\ldots, \\ An=4^{-n}=(\frac{1}{4})^n \end{gathered}[/tex]
So, using the sequence, we can find the expression:
[tex]\begin{gathered} \lim _{n\to\infty}An \\ so\colon \\ \lim _{n\to\infty}An=\lim _{n\to\infty}(\frac{1}{4})^n \\ n\in N \end{gathered}[/tex]
