To solve the given equation isolate the variable z to one of the sides of the equal sign:
[tex]\begin{gathered} 3+\frac{z}{4}=1+\frac{3}{8}z \\ \frac{z}{4}-\frac{3}{8}z=1-3 \\ \frac{z}{4}\cdot\frac{2}{2}-\frac{3}{8}z=-2 \\ \frac{2}{8}z-\frac{3}{8}z=-2 \\ -\frac{1}{8}z=-2 \\ z=-2\cdot-8 \\ z=16 \end{gathered}[/tex]z has a value of 16.
