I am not too sure how to figure out B and C

The given equation is
[tex]d=0.15t[/tex]d is the distance in miles
t is the time in seconds
b. We need to find the distance in 30 seconds
Then substitute t by 30 in the equation
[tex]d=0.15\times30[/tex]The zero in 30 we move the decimal point 1 place to right then
[tex]\begin{gathered} d=1.5\times3 \\ d=4.5\text{ miles} \end{gathered}[/tex]It will travel 4.5 miles in 30 seconds
c. We need to find the time to travel 12.75 miles
Then substitute d in the equation by 12.75
[tex]12.75=0.15t[/tex]Divide 12.75 by 0.15 to find t
[tex]t=\frac{12.75}{0.15}[/tex]The decimal point up will cancel the decimal point down
[tex]\begin{gathered} t=\frac{1275}{15} \\ t=85 \end{gathered}[/tex]It will take 85 seconds to travel 12.75 miles