Respuesta :

The given equation is

[tex]d=0.15t[/tex]

d is the distance in miles

t is the time in seconds

b. We need to find the distance in 30 seconds

Then substitute t by 30 in the equation

[tex]d=0.15\times30[/tex]

The zero in 30 we move the decimal point 1 place to right then

[tex]\begin{gathered} d=1.5\times3 \\ d=4.5\text{ miles} \end{gathered}[/tex]

It will travel 4.5 miles in 30 seconds

c. We need to find the time to travel 12.75 miles

Then substitute d in the equation by 12.75

[tex]12.75=0.15t[/tex]

Divide 12.75 by 0.15 to find t

[tex]t=\frac{12.75}{0.15}[/tex]

The decimal point up will cancel the decimal point down

[tex]\begin{gathered} t=\frac{1275}{15} \\ t=85 \end{gathered}[/tex]

It will take 85 seconds to travel 12.75 miles

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