Respuesta :

X bar stands for the average of the values of X in the data set, and likewise in the case of Y bar; therefore,

Values of Xbar and Ybar

[tex]\begin{gathered} \bar{X}=\frac{18+20+22+25+31+35+38+40+50}{9}=\frac{279}{9}=31 \\ and \\ \bar{Y}=\frac{97}{9} \end{gathered}[/tex]

Then, the answers to the first two columns (top to bottom are)

The first column,[tex]\begin{gathered} X-\bar{X}=18-31=-13\rightarrow first\text{ cell} \\ X-\bar{X}=20-31=-11\rightarrow\text{ second cell} \\ X-\bar{X}=-9 \\ X-\bar{X}=-6 \\ X-\bar{X}=0 \\ X-\bar{X}=4 \\ X-\bar{X}=7 \\ X-\bar{X}=9 \\ X-\bar{X}=19\rightarrow\text{ ninth cell} \end{gathered}[/tex]

Similarly, in the case of the second column

[tex]\begin{gathered} Y-\bar{Y=}14-\frac{97}{9}=\frac{29}{9}\rightarrow\text{ first cell} \\ Y-\bar{Y}=14-\frac{97}{9}=\frac{29}{9}\rightarrow\text{ second cell} \\ \frac{11}{9} \\ \frac{2}{9} \\ -\frac{7}{9} \\ -\frac{7}{9} \\ -\frac{16}{9} \\ -\frac{16}{9} \\ -\frac{25}{9}\rightarrow\text{ ninth cell} \end{gathered}[/tex]

As for the next two columns,

The third column,

[tex]\begin{gathered} (X-\bar{X})^2=(-13)^2=169\rightarrow\text{ first cell} \\ (X-\bar{X})^2=121\rightarrow\text{ second cell} \\ 81\rightarrow\text{ third cell} \\ 36 \\ 0 \\ 16 \\ 49 \\ 81 \\ 361\rightarrow ninth\text{ cell} \end{gathered}[/tex]

Similarly, in the case of the fourth column,

[tex]\begin{gathered} (Y-\bar{Y})^2=\frac{841}{81}\rightarrow\text{ first cell} \\ (Y-\bar{Y})^2=\frac{841}{81}\rightarrow\text{ second cell} \\ \frac{121}{81} \\ \frac{4}{81} \\ \frac{49}{81} \\ \frac{49}{81} \\ \frac{256}{81} \\ \frac{256}{81} \\ \frac{625}{81}\rightarrow\text{ ninth cell} \end{gathered}[/tex]

Calculating Sx,Sy, and SxSy

[tex]\begin{gathered} S_x=\sum_n^(x_n-\bar{X})^2=914 \\ S_y=\sum_n^(y_n-\bar{Y})^2=37.55555=\frac{338}{9} \\ S_xS_y=\frac{308932}{9} \end{gathered}[/tex]

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